0=300-20x+x^2

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Solution for 0=300-20x+x^2 equation: 



0=300-20x+x^2

We move all terms to the left:

0-(300-20x+x^2)=0

We add all the numbers together, and all the variables

-(300-20x+x^2)=0

We get rid of parentheses

-x^2+20x-300=0

We add all the numbers together, and all the variables

-1x^2+20x-300=0

a = -1; b = 20; c = -300;
Δ = b2-4ac
Δ = 202-4·(-1)·(-300)
Δ = -800
Delta is less than zero, so there is no solution for the equation

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